98x^2+8x-30=0

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Solution for 98x^2+8x-30=0 equation:



98x^2+8x-30=0
a = 98; b = 8; c = -30;
Δ = b2-4ac
Δ = 82-4·98·(-30)
Δ = 11824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{11824}=\sqrt{16*739}=\sqrt{16}*\sqrt{739}=4\sqrt{739}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{739}}{2*98}=\frac{-8-4\sqrt{739}}{196} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{739}}{2*98}=\frac{-8+4\sqrt{739}}{196} $

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